Unbalanced neutral loads

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hardworkingstiff

Senior Member
Location
Wilmington, NC
Assuming linear loads and no harmonics:

Single phase would be the difference between amps on the A leg and the amps on the B leg (sharing the neutral).

Three phase would be:
SQRT[(A*A+B*B+C*C)-(A*B+B*C+A*C)]
 
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