feeder calculation

[willdalrymple]

I'm doing the calculation for a fitness club. that is in a strip mall.That has the following items.
1. 3200 square ft X 3 = 9600
2. 30 kw heat. =30,000
3.40 receptacles. =7200
4.8- 16amp treadmills =15,840
5. sign requirement =1200
6.show window =4000
7.10 kw water heater =10,000
_______
77,840


77,840 / (240 x 1.732) = 187.25 = 200amp breaker


since this is a gym and not a store, can I subtract out the show window requirments, and if the treadmills are reduced to 12 amp motors
11,880. This would give a new calculation of.

69,480 / (240 x 1.732) = 167.14 = 175amp breaker and the use of 4/0 al
If you see anything I'm missing let me know.

 

[bphgravity]

Re: feeder calculation

Assuming there is no other equipment or appliances to be served, your calculation looks good. You may want to increase one of the treadmils by 25%, but that won't make much of a difference.

I am also thinking that your lighting load will be continuous. That would include the general purpose lighting, sign, and the show window. All these loads should be increased by 25%. That could make a bit of a difference.

When its all said and done, don't do your customer a dis-service by reducing the service to 175 from 200. The cost difference is very minimal and a slightly larger than required service allows for equipment upgrade and additional loads to be added in the future. Not excatly a code requirement, but don't assume the minimum when it comes to a business. I can think of a half a dozen additional loads that could be desired in a fitness club. Give your customer a little room to work with.

 

[kiloamp7]

Re: feeder calculation

Appears you use 240V 3-phase in your calculation. Is this application for 240/120V. delta with "hi-leg" or is it actually for 208wye/120V.

Is there something I am overlooking.